What is the axis y=-2x^2-2x-2 ?

The axis y=-2x^2-2x-2 is x=-1/2

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axis y=-2x^2-2x-2

axis

y = - 2 x^{2} - 2 x - 2

x = - \frac{1}{2}

Solution steps

y = - 2 x^{2} - 2 x - 2

Rewrite

y = - 2 x^{2} - 2 x - 2

in the standard form

4 (- \frac{1}{8}) (y - (- \frac{3}{2})) = (x - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{2}, - \frac{3}{2}), p = - \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{1}{2}

x^{2} = - 12 y

3 x^{2} + 8 y = 0

y = 3 x^{2} + 9 x + 9

y = 0.07 x^{2} + 20 x + 350

y = (x - 9)^{2} - 2