What is the axis (y+6)^2=12(x+1) ?

The axis (y+6)^2=12(x+1) is y=-6

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axis (y+6)^2=12(x+1)

axis

(y + 6)^{2} = 12 (x + 1)

y = - 6

Solution steps

(y + 6)^{2} = 12 (x + 1)

Rewrite

(y + 6)^{2} = 12 (x + 1)

in the standard form:

4 \cdot 3 (x - (- 1)) = (y - (- 6))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 6), p = 3

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = - 6

y^{2} - 4 x = 0

x^{2} - y = 0

y = 2250 (0.015 - 0.001 x)^{2} + 6000 x

y - 2 = 3 (x - 5)^{2}

y = 160 x - 16 x^{2}