What is the axis y=7x^2 ?

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axis y=7x^2

axis

y = 7 x^{2}

x = 0

Solution steps

y = 7 x^{2}

Rewrite

y = 7 x^{2}

in the standard form:

4 \cdot \frac{1}{28} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{28}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = x^{2} + x + 5

y = 6 x^{2} + 7 x - 3

y = 8 - 2 x^{2}

y = - x^{2} + 6 x + 2

y = (x - 3) (x - 7)