What is the axis 3x^2-9x-2=5y ?

The axis 3x^2-9x-2=5y is x= 3/2

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axis 3x^2-9x-2=5y

axis

3 x^{2} - 9 x - 2 = 5 y

x = \frac{3}{2}

Solution steps

3 x^{2} - 9 x - 2 = 5 y

Rewrite

3 x^{2} - 9 x - 2 = 5 y

in the standard form

4 \cdot \frac{5}{12} (y - (- \frac{7}{4})) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, - \frac{7}{4}), p = \frac{5}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{3}{2}

y = + 2 x^{2} - x - 1

(y - 0)^{2} = 4 x - 4

y = 12 x (x - 4)

x - 2 = (y - 1)^{2}

y = 6 x^{2} - 29 x - 5