What is the axis y=x^2-4x+2 ?

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axis y=x^2-4x+2

axis

y = x^{2} - 4 x + 2

x = 2

Solution steps

y = x^{2} - 4 x + 2

Rewrite

y = x^{2} - 4 x + 2

in the standard form

4 \cdot \frac{1}{4} (y - (- 2)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 2), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

(x - 4)^{2} = 20 (y + 5)

y = (x + 9) (x + 8)

y^{2} + 12 x - 2 y - 11 = 0

(x + 3)^{2} = 12 y

y = x^{2} - 3 x - 40