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Popular >

radius x^2+y^2-25=0

Solution

radius

x^{2} + y^{2} - 25 = 0

Solution

r = 5

Solution steps

x^{2} + y^{2} - 25 = 0

Rewrite

x^{2} + y^{2} - 25 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 5

And the radius is:

r = 5

Popular Examples

foci (x^2)/(36)+(y^2)/(16)=1 foci

\frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

vertices (x^2)/4+(y^2)/9 =1 vertices

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

vertices (y^2)/4-(x^2)/5 =1 vertices

\frac{y ^{2}}{4} - \frac{x ^{2}}{5} = 1

vertices 25x^2+9y^2=225 vertices

25 x^{2} + 9 y^{2} = 225

(x^2)/(100)+(y^2)/(64)=1

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

Frequently Asked Questions (FAQ)

What is the radius x^2+y^2-25=0 ?
The radius x^2+y^2-25=0 is r=5