What is the axis y=x^2+25 ?

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axis y=x^2+25

axis

y = x^{2} + 25

x = 0

Solution steps

y = x^{2} + 25

Rewrite

y = x^{2} + 25

in the standard form:

4 \cdot \frac{1}{4} (y - 25) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 25), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = (2 x - 6)^{2}

y = + 2 x^{2} + 8 x + 4

x = 2 y^{2}

y = (5 - x) (2 x - 3)

y = 3 x^{2} - 15 x + 6