What is the axis x= 1/4 y^2 ?

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axis x= 1/4 y^2

axis

x = \frac{1}{4} y^{2}

y = 0

Solution steps

x = \frac{1}{4} y^{2}

Rewrite

x = \frac{1}{4} y^{2}

in the standard form:

4 \cdot 1 \cdot (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 1

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = 3 x^{2} - 2 x + 2

\frac{y - 2}{4} - \frac{x ^{2}}{9} = 1

y = 2 x^{2} + 24 x - 6

y = (2 x)^{2}

x = + (y + 1)^{2}