What is the axis 12(x-2)=(y+2)^2 ?

The axis 12(x-2)=(y+2)^2 is y=-2

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axis 12(x-2)=(y+2)^2

axis

12 (x - 2) = (y + 2)^{2}

y = - 2

Solution steps

12 (x - 2) = (y + 2)^{2}

Rewrite

12 (x - 2) = (y + 2)^{2}

in the standard form:

4 \cdot 3 (x - 2) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (2, - 2), p = 3

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = - 2

(y - 2)^{2} = 4 (- 10) (x - 2)

y^{2} = - 2 x

y = x^{2} - 3 x - 1

x^{2} - 2 x + 36 y + 28 = 0

y = (x + 1) (x - 5)