What is the axis y=-2x^2+6x+10 ?

The axis y=-2x^2+6x+10 is x= 3/2

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axis y=-2x^2+6x+10

axis

y = - 2 x^{2} + 6 x + 10

x = \frac{3}{2}

Solution steps

y = - 2 x^{2} + 6 x + 10

Rewrite

y = - 2 x^{2} + 6 x + 10

in the standard form

4 (- \frac{1}{8}) (y - \frac{29}{2}) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, \frac{29}{2}), p = - \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{3}{2}

y = - 3 (x + 6)^{2} + 4

y^{2} = - 6 x

y \leq 2 x^{2} - 10 x + 10

y = (x + \frac{1}{2}) (x - \frac{1}{3})

y = (x - \frac{24}{x + 2}) (x - \frac{12}{x - 4})