What is the axis y=-3(x+6)^2+4 ?

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axis y=-3(x+6)^2+4

axis

y = - 3 (x + 6)^{2} + 4

x = - 6

Solution steps

y = - 3 (x + 6)^{2} + 4

Rewrite

y = - 3 (x + 6)^{2} + 4

in the standard form:

4 (- \frac{1}{12}) (y - 4) = (x - (- 6))^{2}

Therefore parabola properties are:

(h, k) = (- 6, 4), p = - \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 6

y^{2} = - 6 x

y \leq 2 x^{2} - 10 x + 10

y = (x + \frac{1}{2}) (x - \frac{1}{3})

y = (x - \frac{24}{x + 2}) (x - \frac{12}{x - 4})

x^{2} = - 8 y