What is the axis 4x^2-24x-40y-4=0 ?

The axis 4x^2-24x-40y-4=0 is x=3

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axis 4x^2-24x-40y-4=0

axis

4 x^{2} - 24 x - 40 y - 4 = 0

x = 3

Solution steps

4 x^{2} - 24 x - 40 y - 4 = 0

Rewrite

4 x^{2} - 24 x - 40 y - 4 = 0

in the standard form

4 \cdot \frac{5}{2} (y - (- 1)) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, - 1), p = \frac{5}{2}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 3

x = + (y + 11)^{2} - 14

y = x^{2} - 3 x + 28

y = (x + 1) x

y = \frac{2 - x ^{2} + 2 x}{3}

y = x^{2} + 2 x - 12