What is the general solution for 1-cos(θ)= 1/2 ?

The general solution for 1-cos(θ)= 1/2 is θ= pi/3+2pin,θ=(5pi)/3+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1-cos(θ)= 1/2

1 - cos (θ) = \frac{1}{2}

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

Solution steps

1 - cos (θ) = \frac{1}{2}

Move

1

to the right side

- cos (θ) = - \frac{1}{2}

Divide both sides by

- 1

cos (θ) = \frac{1}{2}

General solutions for

cos (θ) = \frac{1}{2}

θ = \frac{π}{3} + 2 πn, θ = \frac{5 π}{3} + 2 πn

(tan (θ) - 1) (cos (θ) + 1) = 0

sin^{2} (θ) = cos^{2} (θ)

x, sin (x) = 0

cos (θ) = \frac{2}{5}

2 cos^{2} (x) = cos (x)

What is the general solution for 1-cos(θ)= 1/2 ?
The general solution for 1-cos(θ)= 1/2 is θ= pi/3+2pin,θ=(5pi)/3+2pin