What is the general solution for cos(θ)=-1/(sqrt(2)) ?

The general solution for cos(θ)=-1/(sqrt(2)) is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin

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cos(θ)=-1/(sqrt(2))

cos (θ) = - \frac{1}{2}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

Solution steps

cos (θ) = - \frac{1}{2}

Simplify

- \frac{1}{2} : - \frac{2}{2}

General solutions for

cos (θ) = - \frac{2}{2}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

3 sin (2 t) + 4 = 1

x, cos (x) = 0

cos (x + \frac{π}{6}) - cos (x - \frac{π}{6}) = 1

tan (2 θ) + 2 sin (θ) = 0

2 cos^{2} (x) + 7 sin (x) = 5

What is the general solution for cos(θ)=-1/(sqrt(2)) ?
The general solution for cos(θ)=-1/(sqrt(2)) is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin