What is the general solution for tan^2(2x)=1 ?

The general solution for tan^2(2x)=1 is x= pi/8+(pin)/2 ,x=(3pi)/8+(pin)/2

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tan^2(2x)=1

tan^{2} (2 x) = 1

x = \frac{π}{8} + \frac{πn}{2}, x = \frac{3 π}{8} + \frac{πn}{2}

Solution steps

tan^{2} (2 x) = 1

Solve by substitution

tan (2 x) = 1, tan (2 x) = - 1

tan (2 x) = 1 : x = \frac{π}{8} + \frac{πn}{2}

tan (2 x) = - 1 : x = \frac{3 π}{8} + \frac{πn}{2}

Combine all the solutions

x = \frac{π}{8} + \frac{πn}{2}, x = \frac{3 π}{8} + \frac{πn}{2}

8 cos (x) tan (x) = tan (x)

tan (θ) = - \frac{5}{3}

7 sec (x) csc (x) = 14 csc (x)

sin (7 x) = - \frac{3}{2}

4 sin (θ) - 2 = 0

What is the general solution for tan^2(2x)=1 ?
The general solution for tan^2(2x)=1 is x= pi/8+(pin)/2 ,x=(3pi)/8+(pin)/2