What is the general solution for sin(7x)=-(sqrt(3))/2 ?

The general solution for sin(7x)=-(sqrt(3))/2 is x=(4pi}{21}+(2pin)/7 ,x=(5pi)/(21)+\frac{2pin)/7

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sin(7x)=-(sqrt(3))/2

sin (7 x) = - \frac{3}{2}

x = \frac{4 π}{21} + \frac{2 πn}{7}, x = \frac{5 π}{21} + \frac{2 πn}{7}

Solution steps

sin (7 x) = - \frac{3}{2}

General solutions for

sin (7 x) = - \frac{3}{2}

7 x = \frac{4 π}{3} + 2 πn, 7 x = \frac{5 π}{3} + 2 πn

Solve

7 x = \frac{4 π}{3} + 2 πn : x = \frac{4 π}{21} + \frac{2 πn}{7}

Solve

7 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{21} + \frac{2 πn}{7}

x = \frac{4 π}{21} + \frac{2 πn}{7}, x = \frac{5 π}{21} + \frac{2 πn}{7}

4 sin (θ) - 2 = 0

sin (θ) = - \frac{5}{13}

2 sin^{2} (x) + 5 sin (x) - 3 = 0

- \frac{1}{2} = sin (x)

2 sin (θ) + 4 = 5

What is the general solution for sin(7x)=-(sqrt(3))/2 ?
The general solution for sin(7x)=-(sqrt(3))/2 is x=(4pi}{21}+(2pin)/7 ,x=(5pi)/(21)+\frac{2pin)/7