What is the general solution for 2sin(x)+2=0 ?

The general solution for 2sin(x)+2=0 is x=(3pi)/2+2pin

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2sin(x)+2=0

2 sin (x) + 2 = 0

x = \frac{3 π}{2} + 2 πn

Solution steps

2 sin (x) + 2 = 0

Move

2

to the right side

2 sin (x) = - 2

Divide both sides by

2

sin (x) = - 1

General solutions for

sin (x) = - 1

x = \frac{3 π}{2} + 2 πn

23 cos (θ) sin (θ) - cos (θ) = 2 cos (θ)

cos (2 x) = 2

cos (x) - cos (7 x) = sin (4 x)

cos (\frac{θ}{2}) = 1

csc^{2} (θ) + csc (θ) - 2 = 0

What is the general solution for 2sin(x)+2=0 ?
The general solution for 2sin(x)+2=0 is x=(3pi)/2+2pin