What is the general solution for cos^2(x)=0,5 ?

The general solution for cos^2(x)=0,5 is No Solution for x\in\mathbb{R}

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cos^2(x)=0,5

cos^{2} (x) = 0, 5

No Solution for x \in R

Solution steps

cos^{2} (x) = 0, 5

Apply rule

x^{n} = 0 \Rightarrow x = 0

cos (x) = 0

General solutions for

cos (x) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solutions for the range

5

No Solution for x \in R

2 cos (x) + 3 sin (x) = 2

- cot (x) - 1 = csc (x)

4 sec (θ) + 1 = 9

4 tan^{2} (x) - 12 = 0

tan (θ) - \frac{1}{3} = 0

What is the general solution for cos^2(x)=0,5 ?
The general solution for cos^2(x)=0,5 is No Solution for x\in\mathbb{R}