What is the general solution for 0=4cos(2x) ?

The general solution for 0=4cos(2x) is x= pi/4+pin,x=(3pi)/4+pin

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0=4cos(2x)

0 = 4 cos (2 x)

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solution steps

0 = 4 cos (2 x)

Switch sides

4 cos (2 x) = 0

Divide both sides by

4

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

cos (x) + 2 sin (x) cos (x) = 0, 0 \leq x \leq 2 π

82 cos (θ) + 6 = - 2

cos (- θ) = - cos (θ)

sin^{2} (x) cos (x) = cos (x)

sin (x) = \frac{1}{cos ( x )}

What is the general solution for 0=4cos(2x) ?
The general solution for 0=4cos(2x) is x= pi/4+pin,x=(3pi)/4+pin