What is the general solution for 8sqrt(2)cos(θ)+6=-2 ?

The general solution for 8sqrt(2)cos(θ)+6=-2 is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8sqrt(2)cos(θ)+6=-2

82 cos (θ) + 6 = - 2

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

Solution steps

82 cos (θ) + 6 = - 2

Move

6

to the right side

82 cos (θ) = - 8

Divide both sides by

82

cos (θ) = - \frac{2}{2}

General solutions for

cos (θ) = - \frac{2}{2}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

cos (- θ) = - cos (θ)

sin^{2} (x) cos (x) = cos (x)

sin (x) = \frac{1}{cos ( x )}

tan (x) + 3 cot (x) = 5 sec (x)

6 sin (θ) + 3 = 0

What is the general solution for 8sqrt(2)cos(θ)+6=-2 ?
The general solution for 8sqrt(2)cos(θ)+6=-2 is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin