What is the general solution for sin(x^2+1)-cos(x^2+1)=0 ?

The general solution for sin(x^2+1)-cos(x^2+1)=0 is x=(sqrt(pi+4pin-4))/2 ,x=-(sqrt(pi+4pin-4))/2

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sin(x^2+1)-cos(x^2+1)=0

sin (x^{2} + 1) - cos (x^{2} + 1) = 0

x = \frac{π + 4 πn - 4}{2}, x = - \frac{π + 4 πn - 4}{2}

Solution steps

sin (x^{2} + 1) - cos (x^{2} + 1) = 0

Rewrite using trig identities

tan (x^{2} + 1) - 1 = 0

Move

1

to the right side

tan (x^{2} + 1) = 1

General solutions for

tan (x^{2} + 1) = 1

x^{2} + 1 = \frac{π}{4} + πn

Solve

x^{2} + 1 = \frac{π}{4} + πn : x = \frac{π + 4 πn - 4}{2}, x = - \frac{π + 4 πn - 4}{2}

x = \frac{π + 4 πn - 4}{2}, x = - \frac{π + 4 πn - 4}{2}

cos (θ) = \frac{2}{3}

sin (8 x) = 0

sin (\frac{θ}{2}) = \frac{2}{2}

9 tan (3 x) = 9

sin (θ) = \frac{40}{41}

What is the general solution for sin(x^2+1)-cos(x^2+1)=0 ?
The general solution for sin(x^2+1)-cos(x^2+1)=0 is x=(sqrt(pi+4pin-4))/2 ,x=-(sqrt(pi+4pin-4))/2