What is the general solution for sin^2(θ)+2cos^2(θ)=2 ?

The general solution for sin^2(θ)+2cos^2(θ)=2 is θ=2pin,θ=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin^2(θ)+2cos^2(θ)=2

sin^{2} (θ) + 2 cos^{2} (θ) = 2

θ = 2 πn, θ = π + 2 πn

Solution steps

sin^{2} (θ) + 2 cos^{2} (θ) = 2

Subtract

2

from both sides

sin^{2} (θ) + 2 cos^{2} (θ) - 2 = 0

Rewrite using trig identities

- sin^{2} (θ) = 0

Divide both sides by

- 1

sin (θ) = 0

General solutions for

sin (θ) = 0

θ = 0 + 2 πn, θ = π + 2 πn

Solve

θ = 0 + 2 πn : θ = 2 πn

θ = 2 πn, θ = π + 2 πn

cos (θ) = - c

sin (t) = 1

(tan (x) - 1) (3 tan (x) - 1) = 0

\frac{1 - cos ( 2 x )}{sin ( 2 x )} = 3

2 sin (- 3 x - \frac{π}{4}) = 2, 0 \leq x \leq 2 π

What is the general solution for sin^2(θ)+2cos^2(θ)=2 ?
The general solution for sin^2(θ)+2cos^2(θ)=2 is θ=2pin,θ=pi+2pin