What is the general solution for sin^2(x)-cos(x)=0 ?

The general solution for sin^2(x)-cos(x)=0 is x=0.90455…+2pin,x=2pi-0.90455…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin^2(x)-cos(x)=0

sin^{2} (x) - cos (x) = 0

x = 0.90455 \dots + 2 πn, x = 2 π - 0.90455 \dots + 2 πn

Solution steps

sin^{2} (x) - cos (x) = 0

Rewrite using trig identities

1 - cos (x) - cos^{2} (x) = 0

Solve by substitution

cos (x) = - \frac{1 + 5}{2}, cos (x) = \frac{5 - 1}{2}

cos (x) = - \frac{1 + 5}{2} :

No Solution

cos (x) = \frac{5 - 1}{2} : x = arccos (\frac{5 - 1}{2}) + 2 πn, x = 2 π - arccos (\frac{5 - 1}{2}) + 2 πn

Combine all the solutions

x = arccos (\frac{5 - 1}{2}) + 2 πn, x = 2 π - arccos (\frac{5 - 1}{2}) + 2 πn

Show solutions in decimal form

x = 0.90455 \dots + 2 πn, x = 2 π - 0.90455 \dots + 2 πn

9 sin (x) = cos (x) - 7

tan (θ) = \frac{1}{- 3}

sin^{2} (θ) - cos^{2} (θ) = sin (θ)

4 sin (c) + 3 = sin (c) + 1

(tan (x) + 1) (3 tan (x) - 1) = 0

What is the general solution for sin^2(x)-cos(x)=0 ?
The general solution for sin^2(x)-cos(x)=0 is x=0.90455…+2pin,x=2pi-0.90455…+2pin