What is the general solution for 2cos((2x)/3)-1=0 ?

The general solution for 2cos((2x)/3)-1=0 is x= pi/2+3pin,x=(5pi)/2+3pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos((2x)/3)-1=0

2 cos (\frac{2 x}{3}) - 1 = 0

x = \frac{π}{2} + 3 πn, x = \frac{5 π}{2} + 3 πn

Solution steps

2 cos (\frac{2 x}{3}) - 1 = 0

Move

1

to the right side

2 cos (\frac{2 x}{3}) = 1

Divide both sides by

2

cos (\frac{2 x}{3}) = \frac{1}{2}

General solutions for

cos (\frac{2 x}{3}) = \frac{1}{2}

\frac{2 x}{3} = \frac{π}{3} + 2 πn, \frac{2 x}{3} = \frac{5 π}{3} + 2 πn

Solve

\frac{2 x}{3} = \frac{π}{3} + 2 πn : x = \frac{π}{2} + 3 πn

Solve

\frac{2 x}{3} = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{2} + 3 πn

x = \frac{π}{2} + 3 πn, x = \frac{5 π}{2} + 3 πn

tan (x) + 1 = 0, 0 \leq x \leq 2 π

8 sin^{2} (θ) + 10 sin (θ) - 2 = 4 sin (θ) - 3

tan (x) = - \frac{5}{2}

5 sin^{2} (θ) - 4 cos (θ) - 9 = - cos (θ) - 6

sin (x) + 3 = - sin (x)

What is the general solution for 2cos((2x)/3)-1=0 ?
The general solution for 2cos((2x)/3)-1=0 is x= pi/2+3pin,x=(5pi)/2+3pin