What is the general solution for 2sin^2(x)=4sin(x)+6 ?

The general solution for 2sin^2(x)=4sin(x)+6 is x=(3pi)/2+2pin

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2sin^2(x)=4sin(x)+6

2 sin^{2} (x) = 4 sin (x) + 6

x = \frac{3 π}{2} + 2 πn

Solution steps

2 sin^{2} (x) = 4 sin (x) + 6

Solve by substitution

sin (x) = 3, sin (x) = - 1

sin (x) = 3 :

No Solution

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

cos (x) = sin (1 5^{\circ})

3 = 3 tan (x)

2 cot (x) + 1 = - 1

sin (θ) = \frac{3}{5}, cos (θ)

cos (2 θ) + 2 cos^{2} (θ) = 0

What is the general solution for 2sin^2(x)=4sin(x)+6 ?
The general solution for 2sin^2(x)=4sin(x)+6 is x=(3pi)/2+2pin