What is the general solution for 9sin^2(x)+18sin(x)+9=0 ?

The general solution for 9sin^2(x)+18sin(x)+9=0 is x=(3pi)/2+2pin

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9sin^2(x)+18sin(x)+9=0

9 sin^{2} (x) + 18 sin (x) + 9 = 0

x = \frac{3 π}{2} + 2 πn

Solution steps

9 sin^{2} (x) + 18 sin (x) + 9 = 0

Solve by substitution

sin (x) = - 1

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

- 12 sin^{2} (θ) + 7 = 4

4 cos (θ) + 5 = 0

cos (θ) = \frac{60}{78}

18 sin^{2} (x) = 9

x, sin (x) = cos (y)

What is the general solution for 9sin^2(x)+18sin(x)+9=0 ?
The general solution for 9sin^2(x)+18sin(x)+9=0 is x=(3pi)/2+2pin