What is the general solution for cos^2(x)-cos(x)=0,x,0<= x<= 2pi ?

The general solution for cos^2(x)-cos(x)=0,x,0<= x<= 2pi is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos^2(x)-cos(x)=0,x,0<= x<= 2pi

cos^{2} (x) - cos (x) = 0, x, 0 \leq x \leq 2 π

No Solution for x \in R

Solution steps

cos^{2} (x) - cos (x) = 0, x, 0 \leq x \leq 2 π

Solve by substitution

cos (x) = 1, cos (x) = 0

cos (x) = 1, x :

No Solution

cos (x) = 0, x :

No Solution

Combine all the solutions

No Solution for x \in R

6 cos^{2} (x) + sin (x) - 4 = 0

2 sin (4 x) - 3 = 0

cos (4 x) = \frac{1}{2}, 0 \leq x \leq 2 π

2 cos^{2} (t) + 3 cos (t) - 5 = 0

6 cos^{2} (x) + 7 sin (x) - 8 = 0

What is the general solution for cos^2(x)-cos(x)=0,x,0<= x<= 2pi ?
The general solution for cos^2(x)-cos(x)=0,x,0<= x<= 2pi is No Solution for x\in\mathbb{R}