What is the general solution for 2cos(3θ)=0 ?

The general solution for 2cos(3θ)=0 is θ= pi/6+(2pin)/3 ,θ= pi/2+(2pin)/3

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2cos(3θ)=0

2 cos (3 θ) = 0

θ = \frac{π}{6} + \frac{2 πn}{3}, θ = \frac{π}{2} + \frac{2 πn}{3}

Solution steps

2 cos (3 θ) = 0

Divide both sides by

2

cos (3 θ) = 0

General solutions for

cos (3 θ) = 0

3 θ = \frac{π}{2} + 2 πn, 3 θ = \frac{3 π}{2} + 2 πn

Solve

3 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{6} + \frac{2 πn}{3}

Solve

3 θ = \frac{3 π}{2} + 2 πn : θ = \frac{π}{2} + \frac{2 πn}{3}

θ = \frac{π}{6} + \frac{2 πn}{3}, θ = \frac{π}{2} + \frac{2 πn}{3}

3 sin (x) + tan (x) = 0

2 sin^{4} (x) - cos^{2} (x) = 0

sin (b) = 0.4809

cos^{2} (x) - \frac{3}{4} = 0, 0 \leq x \leq 2 π

sin^{2} (x) - sin (x) - cos^{2} (x) = 0

What is the general solution for 2cos(3θ)=0 ?
The general solution for 2cos(3θ)=0 is θ= pi/6+(2pin)/3 ,θ= pi/2+(2pin)/3