What is the general solution for cos(θ)= 40/41 ?

The general solution for cos(θ)= 40/41 is θ=0.22131…+2pin,θ=2pi-0.22131…+2pin

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cos(θ)= 40/41

cos (θ) = \frac{40}{41}

θ = 0.22131 \dots + 2 πn, θ = 2 π - 0.22131 \dots + 2 πn

Solution steps

cos (θ) = \frac{40}{41}

Apply trig inverse properties

θ = arccos (\frac{40}{41}) + 2 πn, θ = 2 π - arccos (\frac{40}{41}) + 2 πn

Show solutions in decimal form

θ = 0.22131 \dots + 2 πn, θ = 2 π - 0.22131 \dots + 2 πn

- 3 cos (2 θ) + 3 = 5 sin (θ)

12 sin^{2} (x) + 18 sin (x) + 6 = 0

csc^{2} (θ) + cot (θ) = 0

sin^{2} (θ) - 2 sin (θ) - 3 = 0

5 tan (θ) - 4 = 0

What is the general solution for cos(θ)= 40/41 ?
The general solution for cos(θ)= 40/41 is θ=0.22131…+2pin,θ=2pi-0.22131…+2pin