What is the general solution for tan(2x)=0,0<= x<= 2pi ?

The general solution for tan(2x)=0,0<= x<= 2pi is x=0,x= pi/2 ,x=pi,x=(3pi)/2 ,x=2pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan(2x)=0,0<= x<= 2pi

tan (2 x) = 0, 0 \leq x \leq 2 π

x = 0, x = \frac{π}{2}, x = π, x = \frac{3 π}{2}, x = 2 π

Solution steps

tan (2 x) = 0, 0 \leq x \leq 2 π

General solutions for

tan (2 x) = 0

2 x = 0 + πn

Solve

2 x = 0 + πn : x = \frac{πn}{2}

x = \frac{πn}{2}

Solutions for the range

0 \leq x \leq 2 π

x = 0, x = \frac{π}{2}, x = π, x = \frac{3 π}{2}, x = 2 π

arctan (x) = - π

2 sin (2 θ) - 1 = 0

3 sin (θ) = 2 - sin (θ)

tan^{2} (3 t + \frac{π}{2}) = \frac{1}{3}

0 = - 2 sin (2 x)

What is the general solution for tan(2x)=0,0<= x<= 2pi ?
The general solution for tan(2x)=0,0<= x<= 2pi is x=0,x= pi/2 ,x=pi,x=(3pi)/2 ,x=2pi