What is the general solution for 10sin(a)+16=3sin(a)+9 ?

The general solution for 10sin(a)+16=3sin(a)+9 is a=(3pi)/2+2pin

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10sin(a)+16=3sin(a)+9

10 sin (a) + 16 = 3 sin (a) + 9

a = \frac{3 π}{2} + 2 πn

Solution steps

10 sin (a) + 16 = 3 sin (a) + 9

Solve by substitution

sin (a) = - 1

sin (a) = - 1 : a = \frac{3 π}{2} + 2 πn

Combine all the solutions

a = \frac{3 π}{2} + 2 πn

3 sin (x) = 2

(tan (x) + 1) (3 cot (x) - 1) = 0

x, p + 3 q = z + cot (y - 3 x)

4 sin (x) cos (x) = 0

sin (2 x) sin (x) = 0, 0^{\circ} \leq x \leq 36 0^{\circ}

What is the general solution for 10sin(a)+16=3sin(a)+9 ?
The general solution for 10sin(a)+16=3sin(a)+9 is a=(3pi)/2+2pin