What is the general solution for sqrt(3)sec(3x)=2 ?

The general solution for sqrt(3)sec(3x)=2 is x= pi/(18)+(2pin)/3 ,x=(11pi}{18}+\frac{2pin)/3

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sqrt(3)sec(3x)=2

3 sec (3 x) = 2

x = \frac{π}{18} + \frac{2 πn}{3}, x = \frac{11 π}{18} + \frac{2 πn}{3}

Solution steps

3 sec (3 x) = 2

Divide both sides by

3

sec (3 x) = \frac{2 3}{3}

General solutions for

sec (3 x) = \frac{2 3}{3}

3 x = \frac{π}{6} + 2 πn, 3 x = \frac{11 π}{6} + 2 πn

Solve

3 x = \frac{π}{6} + 2 πn : x = \frac{π}{18} + \frac{2 πn}{3}

Solve

3 x = \frac{11 π}{6} + 2 πn : x = \frac{11 π}{18} + \frac{2 πn}{3}

x = \frac{π}{18} + \frac{2 πn}{3}, x = \frac{11 π}{18} + \frac{2 πn}{3}

(sin (x) + cos (x))^{2} = 1

2 sin (3 θ) = 3

sin^{2} (x) + 2 sin (x) = 3

10 (1 - cos (x)) = sin^{2} (x)

2 sin (4 x) = 0

What is the general solution for sqrt(3)sec(3x)=2 ?
The general solution for sqrt(3)sec(3x)=2 is x= pi/(18)+(2pin)/3 ,x=(11pi}{18}+\frac{2pin)/3