What is the general solution for 16cos(2t)=0 ?

The general solution for 16cos(2t)=0 is t= pi/4+pin,t=(3pi)/4+pin

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16cos(2t)=0

16 cos (2 t) = 0

t = \frac{π}{4} + πn, t = \frac{3 π}{4} + πn

Solution steps

16 cos (2 t) = 0

Divide both sides by

16

cos (2 t) = 0

General solutions for

cos (2 t) = 0

2 t = \frac{π}{2} + 2 πn, 2 t = \frac{3 π}{2} + 2 πn

Solve

2 t = \frac{π}{2} + 2 πn : t = \frac{π}{4} + πn

Solve

2 t = \frac{3 π}{2} + 2 πn : t = \frac{3 π}{4} + πn

t = \frac{π}{4} + πn, t = \frac{3 π}{4} + πn

- 2 sin (θ) = - 2

sin (x) = \frac{25}{60}

cos (x) - cos^{2} (x) = 0

tan (x) = 1.25

sin (x^{2}) = cos (x^{2})

What is the general solution for 16cos(2t)=0 ?
The general solution for 16cos(2t)=0 is t= pi/4+pin,t=(3pi)/4+pin