What is the general solution for 8cos^2(x)+16cos(x)+8=0 ?

The general solution for 8cos^2(x)+16cos(x)+8=0 is x=pi+2pin

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8cos^2(x)+16cos(x)+8=0

8 cos^{2} (x) + 16 cos (x) + 8 = 0

x = π + 2 πn

Solution steps

8 cos^{2} (x) + 16 cos (x) + 8 = 0

Solve by substitution

cos (x) = - 1

cos (x) = - 1 : x = π + 2 πn

Combine all the solutions

x = π + 2 πn

cos (x) = - 0.35

cos (x) = - 0.25

1 + sin^{2} (x) = cos^{2} (x)

7 tan (θ) sin (θ) - 6 tan (θ) = 0

2 sin^{2} (x) - 7 cos (x) + 2 = 0

What is the general solution for 8cos^2(x)+16cos(x)+8=0 ?
The general solution for 8cos^2(x)+16cos(x)+8=0 is x=pi+2pin