What is the general solution for 2sin^2(A)=5sin(A)-2 ?

The general solution for 2sin^2(A)=5sin(A)-2 is A= pi/6+2pin,A=(5pi)/6+2pin

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2sin^2(A)=5sin(A)-2

2 sin^{2} (A) = 5 sin (A) - 2

A = \frac{π}{6} + 2 πn, A = \frac{5 π}{6} + 2 πn

Solution steps

2 sin^{2} (A) = 5 sin (A) - 2

Solve by substitution

sin (A) = 2, sin (A) = \frac{1}{2}

sin (A) = 2 :

No Solution

sin (A) = \frac{1}{2} : A = \frac{π}{6} + 2 πn, A = \frac{5 π}{6} + 2 πn

Combine all the solutions

A = \frac{π}{6} + 2 πn, A = \frac{5 π}{6} + 2 πn

cot (θ) = \frac{12}{5}

θ, cos (θ) = - \frac{1}{2}

- 3 sin (b) - 2 = sin (b) - 2

5 sin (2 x) = 2 cos (2 x)

tan (2 θ - 1 0^{\circ}) = cot (θ)

What is the general solution for 2sin^2(A)=5sin(A)-2 ?
The general solution for 2sin^2(A)=5sin(A)-2 is A= pi/6+2pin,A=(5pi)/6+2pin