What is the general solution for 2sqrt(3)+4cos(θ)=0 ?

The general solution for 2sqrt(3)+4cos(θ)=0 is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin

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2sqrt(3)+4cos(θ)=0

23 + 4 cos (θ) = 0

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

Solution steps

23 + 4 cos (θ) = 0

Move

23

to the right side

4 cos (θ) = - 23

Divide both sides by

4

cos (θ) = - \frac{3}{2}

General solutions for

cos (θ) = - \frac{3}{2}

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

2 cos (x) = 1, 0 \leq x < 2 π

cos (x) = - \frac{3}{2}

tan^{2} (x) + 2 tan (x) - 3 = 0

sin (2 x - \frac{π}{3}) = - \frac{1}{2}

2 cos (α) = 3 tan (α)

What is the general solution for 2sqrt(3)+4cos(θ)=0 ?
The general solution for 2sqrt(3)+4cos(θ)=0 is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin