What is the general solution for -25sin(5x)=0 ?

The general solution for -25sin(5x)=0 is x=(2pin)/5 ,x= pi/5+(2pin)/5

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-25sin(5x)=0

- 25 sin (5 x) = 0

x = \frac{2 πn}{5}, x = \frac{π}{5} + \frac{2 πn}{5}

Solution steps

- 25 sin (5 x) = 0

Divide both sides by

- 25

sin (5 x) = 0

General solutions for

sin (5 x) = 0

5 x = 0 + 2 πn, 5 x = π + 2 πn

Solve

5 x = 0 + 2 πn : x = \frac{2 πn}{5}

Solve

5 x = π + 2 πn : x = \frac{π}{5} + \frac{2 πn}{5}

x = \frac{2 πn}{5}, x = \frac{π}{5} + \frac{2 πn}{5}

6 sin^{2} (x) - sin (x) - 1 = 0

sin (x) = \frac{9}{11}

sec^{2} (x) = - 4

0 = 2 sin (x) + 1

cos (θ) = \frac{- 1}{2}

What is the general solution for -25sin(5x)=0 ?
The general solution for -25sin(5x)=0 is x=(2pin)/5 ,x= pi/5+(2pin)/5