What is the general solution for 0=2sin(x)+1 ?

The general solution for 0=2sin(x)+1 is x=(7pi)/6+2pin,x=(11pi)/6+2pin

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0=2sin(x)+1

0 = 2 sin (x) + 1

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solution steps

0 = 2 sin (x) + 1

Switch sides

2 sin (x) + 1 = 0

Move

1

to the right side

2 sin (x) = - 1

Divide both sides by

2

sin (x) = - \frac{1}{2}

General solutions for

sin (x) = - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

cos (θ) = \frac{- 1}{2}

cos^{2} (θ) - cos (θ) - 6 = 0

x, 0 = 1 + cos (x)

1 = 2 sin (2 x)

3 cos (θ) = 2

What is the general solution for 0=2sin(x)+1 ?
The general solution for 0=2sin(x)+1 is x=(7pi)/6+2pin,x=(11pi)/6+2pin