What is the general solution for cos(θ)=(-1)/(sqrt(2)) ?

The general solution for cos(θ)=(-1)/(sqrt(2)) is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin

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cos(θ)=(-1)/(sqrt(2))

cos (θ) = \frac{- 1}{2}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

Solution steps

cos (θ) = \frac{- 1}{2}

Simplify

\frac{- 1}{2} : - \frac{2}{2}

General solutions for

cos (θ) = - \frac{2}{2}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

cos^{2} (θ) - cos (θ) - 6 = 0

x, 0 = 1 + cos (x)

1 = 2 sin (2 x)

3 cos (θ) = 2

cot (t) = - \frac{1}{3}

What is the general solution for cos(θ)=(-1)/(sqrt(2)) ?
The general solution for cos(θ)=(-1)/(sqrt(2)) is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin