What is the general solution for -11tan(x)+1=-2(4+tan(x)) ?

The general solution for -11tan(x)+1=-2(4+tan(x)) is x= pi/4+pin

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-11tan(x)+1=-2(4+tan(x))

- 11 tan (x) + 1 = - 2 (4 + tan (x))

x = \frac{π}{4} + πn

Solution steps

- 11 tan (x) + 1 = - 2 (4 + tan (x))

Solve by substitution

tan (x) = 1

tan (x) = 1 : x = \frac{π}{4} + πn

Combine all the solutions

x = \frac{π}{4} + πn

16 = - 10 cos (\frac{2 π}{150} t) + 10

2 cos (x) - 3 = 0, 0 \leq x \leq 2 π

sec^{2} (x) - 1 = 0, 0 \leq x \leq 2 π

3 cos (\frac{x}{2}) + 3 = cos (\frac{x}{2})

(tan (θ) + 1) (tan (θ) - 3) = 0

What is the general solution for -11tan(x)+1=-2(4+tan(x)) ?
The general solution for -11tan(x)+1=-2(4+tan(x)) is x= pi/4+pin