What is the general solution for 3cot(θ)+5=0 ?

The general solution for 3cot(θ)+5=0 is θ=2.60117…+pin

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3cot(θ)+5=0

3 cot (θ) + 5 = 0

θ = 2.60117 \dots + πn

Degrees

θ = 149.03624 \dots^{\circ} + 18 0^{\circ} n

Solution steps

3 cot (θ) + 5 = 0

Move

5

to the right side

3 cot (θ) + 5 = 0

Subtract

5

from both sides

3 cot (θ) + 5 - 5 = 0 - 5

Simplify

3 cot (θ) = - 5

3 cot (θ) = - 5

Divide both sides by

3

3 cot (θ) = - 5

Divide both sides by

3

\frac{3 cot ( θ )}{3} = \frac{- 5}{3}

Simplify

cot (θ) = - \frac{5}{3}

cot (θ) = - \frac{5}{3}

Apply trig inverse properties

cot (θ) = - \frac{5}{3}

General solutions for

cot (θ) = - \frac{5}{3}

cot (x) = - a \Rightarrow x = arccot (- a) + πn

θ = arccot (- \frac{5}{3}) + πn

θ = arccot (- \frac{5}{3}) + πn

Show solutions in decimal form

θ = 2.60117 \dots + πn

x, h = g

9 cos (2 x) = 10 sin (x) + 1

tan^{2} (x) - 1 = 0, 0 \leq x \leq \frac{π}{2}

10 cos (B) + 6 = 4 cos (B) + 4

2 sin (x) + 2 sin (x) tan (x) = 0

What is the general solution for 3cot(θ)+5=0 ?
The general solution for 3cot(θ)+5=0 is θ=2.60117…+pin