What is the general solution for 4arccos(2x)=pi ?

The general solution for 4arccos(2x)=pi is x= 1/(2sqrt(2))

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4arccos(2x)=pi

4 arccos (2 x) = π

x = \frac{1}{2 2}

Solution steps

4 arccos (2 x) = π

Divide both sides by

4

arccos (2 x) = \frac{π}{4}

Apply trig inverse properties

2 x = \frac{2}{2}

Solve

2 x = \frac{2}{2} : x = \frac{1}{2 2}

x = \frac{1}{2 2}

tan (x) = 2 - 1

5 + 3 cos (\frac{1}{2} x) = 7

cos^{2} (x) sin (x) = sin (x)

sin (2 x - 0.35) = cos (3 x)

2 cos^{2} (x) - 15 cos (x) + 7 = 0

What is the general solution for 4arccos(2x)=pi ?
The general solution for 4arccos(2x)=pi is x= 1/(2sqrt(2))