What is the general solution for 3sin(θ)+5=-2sin(θ) ?

The general solution for 3sin(θ)+5=-2sin(θ) is θ=(3pi)/2+2pin

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3sin(θ)+5=-2sin(θ)

3 sin (θ) + 5 = - 2 sin (θ)

θ = \frac{3 π}{2} + 2 πn

Solution steps

3 sin (θ) + 5 = - 2 sin (θ)

Solve by substitution

sin (θ) = - 1

sin (θ) = - 1 : θ = \frac{3 π}{2} + 2 πn

Combine all the solutions

θ = \frac{3 π}{2} + 2 πn

2 - 4 sin (θ) = 0

2 cos (t) = 1, - π \leq t \leq π

tan (\frac{x}{3}) = 1, 0 \leq x \leq 2 π

4 sin (x) = sin (x) tan (x)

cos (x) = 0.707

What is the general solution for 3sin(θ)+5=-2sin(θ) ?
The general solution for 3sin(θ)+5=-2sin(θ) is θ=(3pi)/2+2pin