What is the general solution for 2sin(x)+10=9 ?

The general solution for 2sin(x)+10=9 is x=(7pi)/6+2pin,x=(11pi)/6+2pin

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2sin(x)+10=9

2 sin (x) + 10 = 9

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solution steps

2 sin (x) + 10 = 9

Move

10

to the right side

2 sin (x) = - 1

Divide both sides by

2

sin (x) = - \frac{1}{2}

General solutions for

sin (x) = - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

cos (x) = - \frac{3}{2}

sin^{2} (x) + 3 sin (x) + 1 = 0

8 sin (b) + 1 = sin (b) + 1

7 cos (3 x) = 7

cos^{2} (θ) = sin^{2} (θ) + 1

What is the general solution for 2sin(x)+10=9 ?
The general solution for 2sin(x)+10=9 is x=(7pi)/6+2pin,x=(11pi)/6+2pin