What is the general solution for 2cos^2(t)-3cos(t)-5=0 ?

The general solution for 2cos^2(t)-3cos(t)-5=0 is t=pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos^2(t)-3cos(t)-5=0

2 cos^{2} (t) - 3 cos (t) - 5 = 0

t = π + 2 πn

Solution steps

2 cos^{2} (t) - 3 cos (t) - 5 = 0

Solve by substitution

cos (t) = \frac{5}{2}, cos (t) = - 1

cos (t) = \frac{5}{2} :

No Solution

cos (t) = - 1 : t = π + 2 πn

Combine all the solutions

t = π + 2 πn

2 + cos (x) = 0

cos (θ) + 2 cos^{2} (θ) = 0

cos (2 x) = - \frac{1}{2}, 0 \leq x \leq 2 π

x, 1 + sin (2 x) = 0

- cos (θ) + 2 cos^{2} (θ) = 0

What is the general solution for 2cos^2(t)-3cos(t)-5=0 ?
The general solution for 2cos^2(t)-3cos(t)-5=0 is t=pi+2pin