What is the general solution for 1+4tan^2(θ)=sec^2(θ) ?

The general solution for 1+4tan^2(θ)=sec^2(θ) is θ=pin

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1+4tan^2(θ)=sec^2(θ)

1 + 4 tan^{2} (θ) = sec^{2} (θ)

θ = πn

Solution steps

1 + 4 tan^{2} (θ) = sec^{2} (θ)

Subtract

sec^{2} (θ)

from both sides

1 + 4 tan^{2} (θ) - sec^{2} (θ) = 0

Rewrite using trig identities

3 tan^{2} (θ) = 0

Divide both sides by

3

tan (θ) = 0

General solutions for

tan (θ) = 0

θ = 0 + πn

Solve

θ = 0 + πn : θ = πn

θ = πn

3 csc (x) = 4 + csc (x)

tan (θ) = - \frac{8}{15}

4 cos (t) = 0

7 sec^{3} (x) + 16 sec^{2} (x) + 11 sec (x) + 2 = 0

1 + sin (5 x) = 0

What is the general solution for 1+4tan^2(θ)=sec^2(θ) ?
The general solution for 1+4tan^2(θ)=sec^2(θ) is θ=pin