What is the general solution for 4cos(t)=0 ?

The general solution for 4cos(t)=0 is t= pi/2+2pin,t=(3pi)/2+2pin

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4cos(t)=0

4 cos (t) = 0

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

Solution steps

4 cos (t) = 0

Divide both sides by

4

cos (t) = 0

General solutions for

cos (t) = 0

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

7 sec^{3} (x) + 16 sec^{2} (x) + 11 sec (x) + 2 = 0

1 + sin (5 x) = 0

0 = \frac{π}{2} - 2 arctan (\frac{\frac{π}{2} - 2 - c}{\frac{π}{2} - c})

9 arcsin (x) = 3 π

2 sin (2 x + 10) - 3 = 0

What is the general solution for 4cos(t)=0 ?
The general solution for 4cos(t)=0 is t= pi/2+2pin,t=(3pi)/2+2pin