What is the general solution for 1+sin(5x)=0 ?

The general solution for 1+sin(5x)=0 is x=(3pi}{10}+\frac{2pin)/5

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1+sin(5x)=0

1 + sin (5 x) = 0

x = \frac{3 π}{10} + \frac{2 πn}{5}

Solution steps

1 + sin (5 x) = 0

Move

1

to the right side

sin (5 x) = - 1

General solutions for

sin (5 x) = - 1

5 x = \frac{3 π}{2} + 2 πn

Solve

5 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{10} + \frac{2 πn}{5}

x = \frac{3 π}{10} + \frac{2 πn}{5}

0 = \frac{π}{2} - 2 arctan (\frac{\frac{π}{2} - 2 - c}{\frac{π}{2} - c})

9 arcsin (x) = 3 π

2 sin (2 x + 10) - 3 = 0

cos (θ) = \frac{13}{6 \cdot 86}

\frac{1 + tan ( x )}{1 + cot ( x )} = 2

What is the general solution for 1+sin(5x)=0 ?
The general solution for 1+sin(5x)=0 is x=(3pi}{10}+\frac{2pin)/5