What is the general solution for -(sqrt(3))/2 =cos(θ) ?

The general solution for -(sqrt(3))/2 =cos(θ) is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin

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-(sqrt(3))/2 =cos(θ)

- \frac{3}{2} = cos (θ)

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

Solution steps

- \frac{3}{2} = cos (θ)

Switch sides

cos (θ) = - \frac{3}{2}

General solutions for

cos (θ) = - \frac{3}{2}

θ = \frac{5 π}{6} + 2 πn, θ = \frac{7 π}{6} + 2 πn

tan (\frac{5 π}{4} + x) + tan (\frac{5 π}{4} - x) = 4

- 8 cos (8 x) = 0

sec^{2} (x) - 4 = 0, 0 \leq x \leq 2 π

tan^{2} (x) + 7 tan (x) + 9 = 0

4 cos (x) = sec (x) + 3, 0 \leq x < 2 π

What is the general solution for -(sqrt(3))/2 =cos(θ) ?
The general solution for -(sqrt(3))/2 =cos(θ) is θ=(5pi)/6+2pin,θ=(7pi)/6+2pin