What is the general solution for -8cos(8x)=0 ?

The general solution for -8cos(8x)=0 is x= pi/(16)+(pin)/4 ,x=(3pi}{16}+\frac{pin)/4

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-8cos(8x)=0

- 8 cos (8 x) = 0

x = \frac{π}{16} + \frac{πn}{4}, x = \frac{3 π}{16} + \frac{πn}{4}

Solution steps

- 8 cos (8 x) = 0

Divide both sides by

- 8

cos (8 x) = 0

General solutions for

cos (8 x) = 0

8 x = \frac{π}{2} + 2 πn, 8 x = \frac{3 π}{2} + 2 πn

Solve

8 x = \frac{π}{2} + 2 πn : x = \frac{π}{16} + \frac{πn}{4}

Solve

8 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{16} + \frac{πn}{4}

x = \frac{π}{16} + \frac{πn}{4}, x = \frac{3 π}{16} + \frac{πn}{4}

sec^{2} (x) - 4 = 0, 0 \leq x \leq 2 π

tan^{2} (x) + 7 tan (x) + 9 = 0

4 cos (x) = sec (x) + 3, 0 \leq x < 2 π

x, - \frac{1}{2 y ^{2}} = 3 sin (x) - \frac{1}{8}

sin (θ) = \frac{150 sin ( 11 5 ^{\circ} )}{212.6}

What is the general solution for -8cos(8x)=0 ?
The general solution for -8cos(8x)=0 is x= pi/(16)+(pin)/4 ,x=(3pi}{16}+\frac{pin)/4